lod[2](3x-5)=3

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Solution for lod[2](3x-5)=3 equation:


Simplifying
lod[2](3x + -5) = 3

Reorder the terms:
dlo * 2(-5 + 3x) = 3

Reorder the terms for easier multiplication:
2dlo(-5 + 3x) = 3
(-5 * 2dlo + 3x * 2dlo) = 3
(-10dlo + 6dlox) = 3

Solving
-10dlo + 6dlox = 3

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Reorder the terms:
-3 + -10dlo + 6dlox = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + -10dlo + 6dlox = 0

The solution to this equation could not be determined.

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